Integrand size = 17, antiderivative size = 100 \[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=-\frac {2 \left (b x+c x^2\right )^{5/2}}{11 b x^8}+\frac {4 c \left (b x+c x^2\right )^{5/2}}{33 b^2 x^7}-\frac {16 c^2 \left (b x+c x^2\right )^{5/2}}{231 b^3 x^6}+\frac {32 c^3 \left (b x+c x^2\right )^{5/2}}{1155 b^4 x^5} \]
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Time = 0.03 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {672, 664} \[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=\frac {32 c^3 \left (b x+c x^2\right )^{5/2}}{1155 b^4 x^5}-\frac {16 c^2 \left (b x+c x^2\right )^{5/2}}{231 b^3 x^6}+\frac {4 c \left (b x+c x^2\right )^{5/2}}{33 b^2 x^7}-\frac {2 \left (b x+c x^2\right )^{5/2}}{11 b x^8} \]
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Rule 664
Rule 672
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \left (b x+c x^2\right )^{5/2}}{11 b x^8}-\frac {(6 c) \int \frac {\left (b x+c x^2\right )^{3/2}}{x^7} \, dx}{11 b} \\ & = -\frac {2 \left (b x+c x^2\right )^{5/2}}{11 b x^8}+\frac {4 c \left (b x+c x^2\right )^{5/2}}{33 b^2 x^7}+\frac {\left (8 c^2\right ) \int \frac {\left (b x+c x^2\right )^{3/2}}{x^6} \, dx}{33 b^2} \\ & = -\frac {2 \left (b x+c x^2\right )^{5/2}}{11 b x^8}+\frac {4 c \left (b x+c x^2\right )^{5/2}}{33 b^2 x^7}-\frac {16 c^2 \left (b x+c x^2\right )^{5/2}}{231 b^3 x^6}-\frac {\left (16 c^3\right ) \int \frac {\left (b x+c x^2\right )^{3/2}}{x^5} \, dx}{231 b^3} \\ & = -\frac {2 \left (b x+c x^2\right )^{5/2}}{11 b x^8}+\frac {4 c \left (b x+c x^2\right )^{5/2}}{33 b^2 x^7}-\frac {16 c^2 \left (b x+c x^2\right )^{5/2}}{231 b^3 x^6}+\frac {32 c^3 \left (b x+c x^2\right )^{5/2}}{1155 b^4 x^5} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.51 \[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=-\frac {2 (x (b+c x))^{5/2} \left (105 b^3-70 b^2 c x+40 b c^2 x^2-16 c^3 x^3\right )}{1155 b^4 x^8} \]
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Time = 2.50 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.55
method | result | size |
gosper | \(-\frac {2 \left (c x +b \right ) \left (-16 c^{3} x^{3}+40 b \,c^{2} x^{2}-70 b^{2} c x +105 b^{3}\right ) \left (c \,x^{2}+b x \right )^{\frac {3}{2}}}{1155 b^{4} x^{7}}\) | \(55\) |
pseudoelliptic | \(-\frac {2 \left (c x +b \right )^{2} \sqrt {x \left (c x +b \right )}\, \left (-16 c^{3} x^{3}+40 b \,c^{2} x^{2}-70 b^{2} c x +105 b^{3}\right )}{1155 x^{6} b^{4}}\) | \(55\) |
trager | \(-\frac {2 \left (-16 c^{5} x^{5}+8 b \,x^{4} c^{4}-6 b^{2} c^{3} x^{3}+5 x^{2} b^{3} c^{2}+140 c x \,b^{4}+105 b^{5}\right ) \sqrt {c \,x^{2}+b x}}{1155 b^{4} x^{6}}\) | \(72\) |
risch | \(-\frac {2 \left (c x +b \right ) \left (-16 c^{5} x^{5}+8 b \,x^{4} c^{4}-6 b^{2} c^{3} x^{3}+5 x^{2} b^{3} c^{2}+140 c x \,b^{4}+105 b^{5}\right )}{1155 x^{5} \sqrt {x \left (c x +b \right )}\, b^{4}}\) | \(75\) |
default | \(-\frac {2 \left (c \,x^{2}+b x \right )^{\frac {5}{2}}}{11 b \,x^{8}}-\frac {6 c \left (-\frac {2 \left (c \,x^{2}+b x \right )^{\frac {5}{2}}}{9 b \,x^{7}}-\frac {4 c \left (-\frac {2 \left (c \,x^{2}+b x \right )^{\frac {5}{2}}}{7 b \,x^{6}}+\frac {4 c \left (c \,x^{2}+b x \right )^{\frac {5}{2}}}{35 b^{2} x^{5}}\right )}{9 b}\right )}{11 b}\) | \(93\) |
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Time = 0.26 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.71 \[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=\frac {2 \, {\left (16 \, c^{5} x^{5} - 8 \, b c^{4} x^{4} + 6 \, b^{2} c^{3} x^{3} - 5 \, b^{3} c^{2} x^{2} - 140 \, b^{4} c x - 105 \, b^{5}\right )} \sqrt {c x^{2} + b x}}{1155 \, b^{4} x^{6}} \]
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\[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=\int \frac {\left (x \left (b + c x\right )\right )^{\frac {3}{2}}}{x^{8}}\, dx \]
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Time = 0.20 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.39 \[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=\frac {32 \, \sqrt {c x^{2} + b x} c^{5}}{1155 \, b^{4} x} - \frac {16 \, \sqrt {c x^{2} + b x} c^{4}}{1155 \, b^{3} x^{2}} + \frac {4 \, \sqrt {c x^{2} + b x} c^{3}}{385 \, b^{2} x^{3}} - \frac {2 \, \sqrt {c x^{2} + b x} c^{2}}{231 \, b x^{4}} + \frac {\sqrt {c x^{2} + b x} c}{132 \, x^{5}} + \frac {3 \, \sqrt {c x^{2} + b x} b}{44 \, x^{6}} - \frac {{\left (c x^{2} + b x\right )}^{\frac {3}{2}}}{4 \, x^{7}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 223 vs. \(2 (84) = 168\).
Time = 0.28 (sec) , antiderivative size = 223, normalized size of antiderivative = 2.23 \[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=\frac {2 \, {\left (2310 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{7} c^{\frac {7}{2}} + 10164 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{6} b c^{3} + 19635 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{5} b^{2} c^{\frac {5}{2}} + 21285 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{4} b^{3} c^{2} + 13860 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{3} b^{4} c^{\frac {3}{2}} + 5390 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{2} b^{5} c + 1155 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )} b^{6} \sqrt {c} + 105 \, b^{7}\right )}}{1155 \, {\left (\sqrt {c} x - \sqrt {c x^{2} + b x}\right )}^{11}} \]
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Time = 9.87 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.23 \[ \int \frac {\left (b x+c x^2\right )^{3/2}}{x^8} \, dx=\frac {4\,c^3\,\sqrt {c\,x^2+b\,x}}{385\,b^2\,x^3}-\frac {8\,c\,\sqrt {c\,x^2+b\,x}}{33\,x^5}-\frac {2\,c^2\,\sqrt {c\,x^2+b\,x}}{231\,b\,x^4}-\frac {2\,b\,\sqrt {c\,x^2+b\,x}}{11\,x^6}-\frac {16\,c^4\,\sqrt {c\,x^2+b\,x}}{1155\,b^3\,x^2}+\frac {32\,c^5\,\sqrt {c\,x^2+b\,x}}{1155\,b^4\,x} \]
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